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What is required when configuring a disk heartbeat device in a PowerHA 6 cluster?
Must be on a shared data volume group disk
Must be an enhanced concurrent volume group
Must be on a shared disk dedicated for diskhb
Must be a resource in a resource group for both nodes
What application specific requirement will prevent it from being used in a PowerHA 7 cluster?
Application must be used with NFSv3
Application must be installed on rootvg
Application must use a specific hostname
Application must be installed on sharedvg
If an application stop script fails during selective failover process, which action will recover the production service as soon as possible?
Wait for time-out via config_too_long event.
Select "Recover From HACMP Script Failure" from SMIT
Halt the node on which application stop script has failed.
Force shutdown all nodes in the cluster for data integrity.
A customer notices the following event in hacmp.out. EVENT START: cluster_notify NODE1 1 Sep 15 00:01:53 NOTIFY
COMMAND:/usr/es/sbin/cluster/utilities/clissuepage NODE1 clverify has detected cluster configuration errors on node NODE1. Why did this event occur?
Automatic error notification has detected a cluster error and notified the dstrmgrES.
Cluster verification has been initiated by the administrator and errors have been logged to hacmp.out.
Automatic cluster verification has been configured and an error was detected with the cluster configuration.
Notification has been sent that the cluster test tool automated procedure completed and has been logged in hacmp.out.
Which fileset must be installed to enable message authentication and encryption?
A 2-node cluster has startup monitoring. The Action on Application failure of monitoring is set to "notify." The startup policy of the cluster is "Online on Home Node Only." The home node isNode1. Node 2 is up. If startup monitoring detects a failure during Node 1 startup, what will the state of the resource group be?
ERROR Node1 ONLINE Node2
ERROR Node1 OFFLINE Node2
OFFLINE Node1 ONLINE Node2
OFFLINE Node1 OFFLINE Node2
A shared volume group (VG) was created in a PowerHA 7 environment. Given the following example, what must be changed in the VG definition?
Set QUORUM to 1(Disabled).
Set BB POLICY to relocatable.
Set concurrent capable to enhanced concurrent.
Set hot spare characteristics to yes(one to one).
Complete the following statement:
With a cluster using EtherChannel backup for high availability of network interfaces, the netmon.cf file setting is not needed for local network failure detection if EtherChannel backup has :
address to ping attribute
multiple EtherChannel devices
alternate EtherChannel address
enabled automatic recovery after failover
The db_group resource group become unmanaged after cluster service onnode1is forced down. Which action will change the state of db_group resource group from unmanaged to Online on node2?
Bring db_group Online directly on node2
Move resource group db_group from node1 to node2
Bring db_group offline and then bring db_group Online on node2
Run clchres utility to change the state of db_group resource to Online on node2
An administrator has written a custom verification method script and wants it distributed to all nodes in the cluster during cluster synchronization. Which file collection should be changed to "Propagate files during cluster synchronization?"
After changing a PowerHA 6 cluster to reflect new IP addresses, an administrator attempts to synchronize a cluster and receives the following message: cldare: A communication error prevents obtaining the VRMF from remote nodes. A DARE cannot be run until this is corrected. Please ensure clcomd is running. How can the administrator correct this error?
Include the new IP addresses in /.rhosts on all cluster nodes.
Include the new IP addresses in /etc/hosts.equiv on all cluster nodes.
Include the new IP addresses in /usr/es/sbin/cluster/etc/rhosts on all cluster nodes.
Include the new IP addresses in /usr/es/sbin/cluster/etc/clhosts on all cluster nodes.
A new application is added to the cluster and verification produces an error. What is the most likely reason?
The application is running on one of the cluster nodes.
Some application dependencies are missing from one or more nodes in the resource group.
The application start script is not executable on one of the nodes in the resource group.
The size of the application start script is not the same on all of the nodes in the resource group.
IBM 000-332 Exam (High Availability for AIX - Technical Support and Administration -v2) Detailed Information
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C4040-332 - high Availability for AIX - Technical help and Administration -v2No result discovered, are trying new key phrase!excessive Availability for AIX -Technical support and Administration -v2.000-332.v45-5.2016-03-13.1e.50q.examination 205 Kb Mar 16, 2016 high Availability for AIX -Technical aid and Administration -v2.000-332.v12-49.2013-06-08.1e.135q.examination 6.seventy four Mb Aug 02, 2015 IBM LOT-988 : Administering IBM Lotus Sametime eight.5 examination
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Let x denote the lengths of the two aspects which come
Unformatted textual content preview: Let x denote the lengths of the two sides which come faraway from the river, and let y denote the size of fencing parallel to the river. Then we wish to maximize the entire volume of area, which is A = xy. we are told that we now have 5,000 toes of fencing, so we have that 5 , 000 = 2 x + y. therefore y = 5 , 000- 2 x, which gives A = x (5 , 000- 2 x ) = 5 , 000 x- 2 x 2 . we're instructed that each x and y need to be as a minimum 100 toes. So x a hundred , and considering that y 100 we get 5 , 000- 2 x a hundred , x 2 , 450 . So the appropriate interval for x is [100 , 2450]. To locate the optimum price for A we compute A = 5 , 000- four x , and set it equal to zero, and clear up for x . (notice that A exists for all values of x .) This offers 5000- 4 x = 0 , so that x = 1250. Now use the Closed Interval components. We plug within the three values 100 , 1250 , and 2450 in for x in the area formulation, and see which offers a 1 maximum. A (1250) = 5000 1250- 2(1250) 2 = three , one hundred twenty five , 000 sq. toes. A (a hundred) = a hundred 4800 = 480 , 000 sq. toes. A (2450) = 2450 a hundred = 245 , 000 sq toes. thus the optimum area happens when x = 1250, in order that each of the sections of fencing coming faraway from the river are 1250 ft lengthy, and the component to fencing parallel to the river is 2500 ft lengthy. b. How much total enviornment is enclosed in the pasture you have pictured above? A (1250) = 3 , 125 , 000 square toes. 5. (7 pt total) A espresso producer has been selling one thousand baggage per week at $450 per bag. A survey of the producers shoppers indicates that for each and every drop in fee of $10 per bag, the variety of baggage offered per week will increase by 100. think the weekly cost function to provide and promote x bags is C ( x ) = 68 , 000 + a hundred and fifty x . The means of the plant is 5000 baggage per week. a. locate the (linear) demand function; i.e., discover the linear characteristic which offers the relationship between x (the number of bags offered per week) when it comes to p (the fee per bag). So we have that, as an instance, p = 450 when x = one thousand, and p = 440 when x = 1100. The slope of the line (viewing p as outputs, x as inputs) is 450- 440 1000- 1100 = 10- one hundred =- 1 10 . So the linear price demand feature is p- 450 =- 1 10 ( x- 1000), which gives p =- 1 10 x + 550. (be aware: You could have additionally solved for x in terms of p , this could have given x =- 10 p + 5500.) b. discover the income function for this producer as a feature of x . (Reminder: the profit ( x ) equals R ( x )- C ( x ), where R ( x ) is the profits generated by way of producing / promoting x baggage.) ( x ) = R ( x )- C ( X ) = x p- C ( x ) = x (- 1 10 x + 550)- (sixty eight , 000 + a hundred and fifty x ) =- 1 10 x 2 + 400 x- sixty eight , 000. c. What degree of weekly construction / earnings will maximize the producers weekly profit? We use the Closed interval formulation. The given info in regards to the flowers creation skill gives that acceptable domain for x is 0 x 5000. We discover the crucial values of ( x ). ( x ) =- 2 10 x + four hundred =- 1 5 x + four hundred. surroundings ( x ) = 0 gives x = 2000 . So we check the values of ( x ) for the three input values 0 , 2000 , 5000. (0) =- 68000; (2000) =- 1 10 2000 2 + 400(2000)- 68 , 000 = 332 , 000; (5000) =- 1 10 5000 2 + 400(5000)- 68 , 000 =- 568 . 000;....View Full document